User Tools

Site Tools


tutorial_15-implementing_using_one_compartment

Tutorial 15 - Implementing using one compartment

3/3

When implementing the Lotka-Volterra model using one Compartment block (one for both the predator and prey), the compartment needs to be vectorized. I.e. the rabbit and fox species needs to be added as modelled materials or created as indexes from Index-list. Then either one can use the same approach as in the two Compartment solution, using Source/Sink and Transfer blocks as means to model the dynamic behaviour or just explicitly define the differential equation inside the Compartment.

Option 1

Create parameters according to table below:

Parameter Unit Value Description
a 1/year 0.04 the natural growth rate of rabbits in the absence of predation
c 1/year 0.2 the natural death rate of foxes in the absence of food (rabbits)
b 1/(year F)5.0E-4the death rate per encounter of rabbits due to predation
e F/R 0.1 the efficiency of turning predated rabbits into foxes
Init_population n Initial animal population

Values for parameter Initial population:

  • Init_population[Rabbits]= 1000
  • Init_population[Foxes]= 4

Create source, sink, compartments and transfer according to picture below:

Equations for Transfers:

  • AnimalBirth[Rabbits]=Animals·a
  • AnimalBirth[Foxes]=Animals[Rabbits]·Animals[Foxes]·e·b
  • AnimalDeath[Rabbits]=b·Animals[Rabbits]·Animals[Foxes]
  • AnimalDeath[Foxes]=c·Animals

Initial Conditions for compartment:

  • For Animals[Rabbits] = Init_population
  • For Animals[Foxes] = Init_population

Option 2

Create parameters according to table below:

Parameter Unit Value Description
a 1/year 0.04 the natural growth rate of rabbits in the absence of predation
c 1/year 0.2 the natural death rate of foxes in the absence of food (rabbits)
b 1/(year F)5.0E-4the death rate per encounter of rabbits due to predation
e F/R 0.1 the efficiency of turning predated rabbits into foxes

Create only one compartment with name Animals.

Initial Conditions for compartment:

  • For Animals[Rabbits] = 1000
  • For Animals[Foxes] = 4

dy/dt for compartment:

  • Rabbits: dAnimals/dt=Animals[Rabbits]·a-b·Animals[Rabbits]·Animals[Foxes]
  • Foxes: dAnimals/dt=Animals[Rabbits]·Animals[Foxes]·e·b-c·Animals[Foxes]


Solution to the excersise

Previous

References

tutorial_15-implementing_using_one_compartment.txt · Last modified: 2023/04/03 17:38 by dmytroh